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Large data set: weather context

Understand the places, dates and limits of the Pearson Edexcel weather large data set. Choose a meaningful population and interpret seasonal comparisons.

Before you startPopulations, samples and types of data.

01 / Begin with the context

A table is evidence about particular places and times.

Pearson Edexcel’s large data set contains Met Office weather records for eight stations.

The periods are May–October in 1987 and May–October in 2015.

Five stations are in the UK: Camborne, Heathrow, Hurn, Leeming and Leuchars. Three are overseas: Beijing, Jacksonville and Perth. These are selected stations and selected months, not every place or day in the world.

This lesson describes the Pearson Edexcel context. Other awarding bodies may use different data sets.

Reference: Pearson qualification and assessment guide, page 9. Use the official workbook alongside these original explanations when investigating the actual records.

Place, year and seasonExplore

Camborne: UK, Northern hemisphere.

May–October 1987: 184 calendar days.

This window spans late spring, summer and autumn in the Northern hemisphere.

The controls describe the data context, not measured weather values. A calendar day count does not guarantee 184 usable readings for every variable.

02 / Identify one observation

Specify station, date and variable.

A daily temperature observation needs a station and a date. “July temperature” is incomplete without specifying the location, year and whether you mean one day’s mean, a monthly average, a maximum or another summary.

Each date can have several variables. Temperature, rainfall and wind speed are different measurements for that day; they are not interchangeable observations of one quantity.

01 · Make the observation precise

Improve the description “a temperature from the data set”.

Hint

Identify location, date and the type of temperature.

Worked solution

For example: the daily mean temperature at Hurn on 12 July 2015, measured in degrees Celsius. This specifies a possible record; it does not assert its numerical value.

02 · Count observations correctly

A table has 20 dates and three measured variables per date. How many daily observations of rainfall are potentially available?

Hint

Count dates for the rainfall variable, not all numerical cells.

Worked solution

Twenty, before allowing for any missing rainfall entries. Sixty cells do not mean sixty independent rainfall days.

03 / Read the time window

Six months are not a full year.

Count the dates from May to October inclusive.Worked example

31 + 30 + 31 + 31 + 30 + 31 = 184

Include May, June, July, August, September and October.

184 × 2 = 368 dates per station across the two periods

This is a calendar count, before missing observations.

8 × 368 = 2,944 station-date combinations

Several stations on one date still form different station-date records.

03 · A whole-year claim

Can the May–October mean rainfall directly be called the mean daily rainfall for the whole year?

Hint

Which months are excluded?

Worked solution

No. November–April are absent. Weather is seasonal, so the included period need not represent the whole year.

04 · Two years apart

How many years separate 1987 and 2015? Does the workbook provide every intervening year?

Hint

Subtract, then distinguish a gap from a continuous sequence.

Worked solution

28 years. No: these are two selected periods, not an annual series for all years in between.

04 / Compare like with like

The same month can mean different seasons.

The UK, Beijing and Jacksonville are in the Northern hemisphere. Perth is in the Southern hemisphere. May–October includes Northern summer and Southern winter. The full six-month window also crosses seasonal transitions, so it is too crude to label every included day simply “summer” or “winter”.

Latitude, altitude, coastal influence and local conditions can also matter. Hemisphere alone does not predict the actual temperature on a particular day.

Watch: the same months span different seasons

Pause, replay or seek freely. The notes explain the same idea and stay in view.

05 · A comparison with Perth

A student compares UK July temperatures with Perth July temperatures and concludes that every difference is caused by one site having a colder climate. Give a missing consideration.

Hint

July is not the same season in both hemispheres.

Worked solution

July is in Northern summer and Southern winter. Season is a relevant contextual difference; the comparison alone cannot isolate a single cause.

05 / Read headings and units

A number without its variable is ambiguous.

Weather variables include daily mean temperature, rainfall totals and wind measurements. Read the exact workbook heading and its unit before calculating or labelling a graph. For example, temperature in °C and wind speed in knots measure different quantities.

A daily mean and a daily maximum are different summaries. Wind direction is directional data: ordinary arithmetic averages of compass bearings can mislead near the wrap from 360° to 0°. Do not silently combine columns with different definitions.

06 · Mean versus maximum

Why should a daily maximum gust not be treated as the daily mean wind speed?

Hint

One records an extreme; the other describes an average.

Worked solution

They are different variables. The largest gust can be much greater than the mean; use the requested column and label its statistic correctly.

07 · Compass wrap

Bearings of 1° and 359° are both almost north. Why is their ordinary arithmetic mean of 180° misleading?

Hint

Directions wrap around a circle.

Worked solution

180° points south, far from both directions. Circular direction requires a suitable method; do not treat bearings as ordinary linear measurements.

06 / Unfamiliar weather units

Convert the unit, not the underlying observation.

  • Wind speed: knots. One knot is one nautical mile per hour, equal to 1.852 km/h.
  • Cloud cover: oktas, describing eighths of the sky covered; 0 means clear and 8 means fully covered.
  • Visibility: decametres in this data set. One decametre is 10 metres, so 100 decametres is 1 kilometre.
  • Pressure: hectopascals (hPa). One hectopascal is 100 pascals.

These definitions help interpret magnitude. They do not make the measurements exact or remove missing values. Distinguish the underlying cloud fraction from a recorded whole-okta value.

Pearson confirms wind-speed units, cloud-cover units, visibility units and pressure units in its assessment materials.

08 · Interpret visibility

An invented visibility reading is 1,250 decametres. Convert it to kilometres.

Hint

Multiply by 10 for metres, then divide by 1,000.

Worked solution

1,250 × 10 = 12,500 m = 12.5 km.

09 · Cloud fraction

What fraction of the sky is represented by 6 oktas?

Hint

An okta is one eighth.

Worked solution

6/8 = 3/4, or 75%.

10 · Convert wind speed

Use 1 knot = 1.852 km/h to convert an invented reading of 15 knots.

Hint

Multiply the numerical speed by the conversion factor.

Worked solution

15 × 1.852 = 27.78 km/h.

07 / Define the intended conclusion

A census of a sheet may still be a sample of a wider world.

Using every available daily rainfall entry for one station and one period can be a census of that defined set of recorded entries. It does not automatically describe all weather at the station in other years, all of the surrounding region or all UK weather.

11 · Narrow and broad populations

A researcher uses every available Heathrow daily mean temperature from May–October 2015. State one narrow population directly covered and one broader population not fully covered.

Hint

Keep the time and location restrictions explicit.

Worked solution

The available recorded daily means for Heathrow in that period are covered. All daily means across the UK throughout 2015 are not: other locations and months are missing.

08 / Select a sample that answers the question

Use an explicit frame of eligible records.

To sample ten dates from one station-year period, first define the eligible dates and decide how missing data will be handled. Assign labels and select distinct dates randomly. If comparing two variables, retain their pairing for each chosen date.

For a comparison by month, proportional stratification can help preserve month representation. Choosing the first ten visible rows is an opportunity-style selection of records, not a simple random sample.

12 · Keep pairs together

You investigate sunshine and temperature on 15 sampled dates. Why should the two columns stay aligned by date?

Hint

The association concerns the two measurements on the same day.

Worked solution

Sorting one column independently destroys the original pairing and creates false pairs. Keep station and date identifiers with the measurements.

13 · An inappropriate frame

A sample is selected only from July rows, then used to describe all May–October days. What is the coverage problem?

Hint

Five included months cannot be selected.

Worked solution

May, June, August, September and October are excluded from the sampling frame. Seasonal differences may make the July sample unrepresentative of the six-month period.

09 / Avoid conclusions the data cannot support

Two selected years do not establish a long-term trend.

A difference between a statistic in 1987 and 2015 describes that comparison. It does not by itself establish a long-term climate trend or prove its cause. A longer, suitably analysed series and relevant scientific evidence would be needed for those claims.

Missing values and unusual records need investigation and clear handling rules; they are not permission to delete inconvenient evidence. The next lesson examines trace rainfall and missing entries.

14 · A claim too far

A station has a larger sample mean in 2015 than in 1987. Why is “the temperature increased every year between them” unsupported?

Hint

The intervening annual values are not in the comparison.

Worked solution

A difference between two selected samples gives no information about the direction of every intervening yearly change. Sampling variation and the restricted months also matter.

10 / Place, time, variable, population

State the context before calculating.

  1. Name the station and year.
  2. Check the May–October window.
  3. Read the exact variable and unit.
  4. Account for season and hemisphere.
  5. Define the population and eligible frame.
  6. Keep paired observations together.
  7. Limit the conclusion to what the design supports.

15 · Plan a fair comparison

You want to compare daily mean temperature at two UK stations in the same period. Give three design choices that make your comparison interpretable.

Hint

Think about dates, variable definitions and missing entries.

Worked solution

Use the same year and comparable date window; use daily mean temperature in the same unit at both stations; state a consistent missing-data policy and sampling design. Keeping matched dates can help avoid comparing different seasonal slices. Report that the result concerns those stations and dates.

Section 1 of 10 · Begin with the context