01 · Complete bars
Bars over [0,5) and [5,15) have densities 2 and 3. Find their frequencies and total.
Hint
Use widths 5 and 10.
Worked solution
Frequencies 10 and 30; total 40.
Understand · explore · practise
Recover complete class counts and estimate threshold or interval counts using histogram areas, with explicit uniformity assumptions and appropriate precision.
Before you startFrequency density, areas and fractions of intervals.
01 / Identify the required area
With true density axes, count in a full class = width×density.
For part of a class, selected width×density is a model-based estimate.
A histogram’s flat top does not prove the hidden observations were evenly distributed. The picture represents the average frequency per unit across a class; partial-bar calculations use an additional uniformity assumption.
Classes [0,10), [10,20), [20,40) have frequencies 6, 8, 12. Total n = 26. Density is constant within each drawn bar.
Below 5: estimated count 3 under uniform within-class spread.
Complete class counts are known. A fraction of a bar estimates how its observations divide only when a within-class model is assumed.
02 / Recover complete class counts
Full width = 20
Use the boundaries.
Full class count = 20×0.6 = 12
The count is represented by the whole rectangle.
Two adjacent full bars contribute the sum of their areas
Do not multiply the total width by just one of their heights.
Bars over [0,5) and [5,15) have densities 2 and 3. Find their frequencies and total.
Use widths 5 and 10.
Frequencies 10 and 30; total 40.
Why is (15 − 0)×3 wrong for the total in question 1?
Density 3 applies only to the second interval.
It assigns the second height to the first interval too. Add 5×2 + 10×3 = 40 instead of 45.
03 / Take a fraction of a class
Pause, replay or seek freely. The notes explain the same idea and stay in view.
Estimated partial count = full class frequency × selected width / full width.
Equivalently, multiply the selected width by that class density.
Class [10,20) contains 8 observations. Estimate how many are below 15 within that class.
The selected width is 5 of the full 10.
Estimate 8×5/10 = 4, assuming uniform spread within the class. The actual count need not be four.
Class [0,12) contains 5 observations. Estimate the count in [0,3).
The selected interval is one quarter of the width.
Estimate 5×3/12 = 1.25. This is a model estimate, not an exact possible observed count; report or round only as the question requires.
04 / Cross several bars
Using the model, estimate the count in [5,15).
Take the upper half of the first bar and lower half of the second.
Estimate 6×5/10 + 8×5/10 = 3 + 4 = 7.
Using the model, estimate the count in [5,30).
Include the complete middle class.
Estimate 3 + 8 + 12×10/20 = 17. The first and last contributions assume uniformity; the middle count is known.
05 / Use a complementary count
Using the model, estimate how many observations are at least 25.
Only [25,40) contributes.
Estimate 12×15/20 = 9. Equivalently, estimated count below 25 is 6 + 8 + 3 = 17, so 26 − 17 = 9.
How many model observations are at least 20?
The last class includes 20.
Exactly 12 under the stated [lower,upper) classes. A threshold at a supplied class boundary can use whole class frequencies without within-class interpolation.
06 / Divide by the right total
Estimate the percentage of model observations below 15.
The estimated count is 6 + 4 = 10, out of 26.
About 100×10/26 = 38.46%, under the uniformity model. The exact interior-threshold percentage is not determined by the grouped counts alone.
A selected histogram area represents 8 observations out of 20 in A and 12 out of 40 in B. Which proportion is larger?
Normalise each count by its own sample size.
A: 40%; B: 30%. B has the larger count but the smaller proportion.
07 / Find a threshold from a target count
The first class contributes 6
Another 7 are needed from the middle class.
Middle density = 8/10 = 0.8
A count of 7 corresponds to width 7/0.8 = 8.75.
Estimated median = 10 + 8.75 = 18.75
This agrees with linear cumulative interpolation.
Using the model, estimate t such that 20 observations are below t.
Fourteen lie below 20, so 6 more are needed from the final class.
Final density 0.6 gives width 6/0.6 = 10. Thus t ≈ 30.
Can a threshold contain 30 of the model’s observations below it?
The total is 26.
No. A cumulative target cannot exceed the whole dataset count. Check the requested count or whether the diagram covers a larger dataset.
08 / Separate possible counts from estimates
Class [10,20) contains 8 observations. Without a uniformity assumption, what are the possible counts below 15 within it?
All eight might lie on either side of 15.
Any integer from 0 to 8 is possible. The estimate 4 is not a guaranteed count.
You know only a dataset’s mean and SD. Can you perform a partial-histogram-area calculation to find the count beyond one SD?
No histogram frequencies or distribution shape have been given.
No. A mean and SD do not determine the required areas. Additional class counts or an explicitly stated distributional model are needed.
09 / Add the right rectangles
Recover complete class areas exactly when the scale is known. For thresholds inside classes, state uniformity, combine partial and full contributions and use the correct total for percentages. Do not turn a modelled fractional count into a claim about exact observed records.
Section 1 of 9 · Identify the required area