01 · Average and half-difference
For A = 7x and B = 3x, find M and D.
Hint
Add or subtract before dividing by 2.
Worked solution
M = 5x and D = 2x.
Understand · explore · practise
Derive sum to product and product to sum formulae from compound angles. Evaluate exact expressions, factor trigonometric equations, retain zero factors and check quotient domains.
Before you startCompound angle formulae, exact values and periodic root sets
01 / Use the average and half-difference of the angles
Let M = (A + B)/2 and D = (A − B)/2. Then A = M + D and B = M − D. Adding or subtracting the corresponding compound-angle expansions produces useful products.
M = (A + B)/2, D = (A − B)/2
A = M + D, B = M − D
The model links this algebra to a combined wave. Its product form explains why the curve stays between the blue envelopes and where its zero factors can occur.
sin(5x) + sin(3x) = 2sin(4x)cos(x).
At x = 30°: A = 150°, B = 90°; M = 120°, D = 30°.
Sum/difference = 1.5000. Product = 1.5000.
Gold is the combined wave. Blue dashed curves are the positive and negative product envelopes. The remaining sine or cosine factor stays between −1 and 1. Decimal readouts are rounded to four places.
02 / Add and subtract the sine expansions
Expand sin(M + D) = sin M cos D + cos M sin D and sin(M − D) = sin M cos D − cos M sin D.
sin A + sin B = 2sin((A + B)/2)cos((A − B)/2)
sin A − sin B = 2cos((A + B)/2)sin((A − B)/2)
In the sum, the cosine-sine terms cancel. In the difference, the sine-cosine terms cancel. These identities hold for every real A and B.
Pause, replay or seek freely. The notes explain the same idea and stay in view.
03 / Subtract cosine expansions carefully
Expand cos(M + D) = cos M cos D − sin M sin D and cos(M − D) = cos M cos D + sin M sin D.
cos A + cos B = 2cos((A + B)/2)cos((A − B)/2)
cos A − cos B = −2sin((A + B)/2)sin((A − B)/2)
Keep the order A − B consistent. If you reverse the half-difference, its sine changes sign and the leading minus must change too.
04 / Read the identities backwards to turn products into sums
2sin u cos v = sin(u + v) + sin(u − v)
2cos u cos v = cos(u + v) + cos(u − v)
2sin u sin v = cos(u − v) − cos(u + v)
sin 5x cos 2x = (sin 7x + sin 3x)/2
Divide the first product identity by 2.
sin 5x sin 2x = (cos 3x − cos 7x)/2
The difference-angle cosine comes first.
For 2cos u sin v, commute the two factors and use the first identity with their roles swapped. This gives sin(u + v) − sin(u − v).
05 / Choose sums with familiar averages and half-differences
The average is 45° and the half-difference is 30°
Compute these before selecting a formula.
sin 75° + sin 15° = 2sin 45° cos 30° = √6/2
The sum uses sine of the average.
cos 75° − cos 15° = −2sin 45° sin 30° = −√2/2
The negative sign is essential.
06 / Factor a sum before solving it
sin 4x + sin 2x = 2sin 3x cos x
Use average 3x and half-difference x.
sin 3x = 0 or cos x = 0
Do not divide by either trig factor.
x = 0°, 60°, 120°, 180°, 240°, 300°, 360° from sine
List every multiple-angle root in the interval.
x = 90°, 270° from cosine
These give two additional roots.
Combine the two lists
The complete set has nine distinct solutions.
07 / Merge roots shared by two factors
2sin 4x cos x = 0
Factor using the sum formula.
sin 4x = 0 gives x = 45°k
Take k = 0, 1, …, 8.
cos x = 0 gives x = 90°, 270°
Both already belong to the first list.
The complete set is 0°, 45°, 90°, 135°, 180°, 225°, 270°, 315°, 360°
There are nine roots, not eleven.
It would still be invalid to divide by cos x without checking its zeros separately, even though in this particular example those roots happen to be recovered by the other factor.
08 / Use a cosine difference to reveal two sine factors
cos 5x − cos x = −2sin 3x sin 2x
The average is 3x and the half-difference 2x.
sin 3x = 0 or sin 2x = 0
The constant −2 is never zero.
The first family is x = 60°k; the second is x = 90°k
Filter both into the required interval.
x = 0°, 60°, 90°, 120°, 180°, 240°, 270°, 300°, 360°
Merge shared endpoints and the shared root 180°.
09 / After cancellation, keep the original denominator restrictions
The numerator is 2sin 4x cos x
Factor the sine sum.
The denominator is 2cos 4x cos x
The original domain requires cos 4x cos x ≠ 0.
The quotient is tan 4x on that domain
Cancel the nonzero factor 2cos x.
At x = 90°, tan 4x = 0 but the original quotient is undefined
Cancellation cannot restore the excluded cos x = 0 inputs.
10 / Your turn
For A = 7x and B = 3x, find M and D.
Add or subtract before dividing by 2.
M = 5x and D = 2x.
Factor sin 7x + sin 3x.
Use the previous average and half-difference.
2sin 5x cos 2x, for every real x.
Factor sin 7x − sin 3x.
The difference uses cosine of the average.
2cos 5x sin 2x.
Factor cos 7x + cos 3x.
Both factors are cosines.
2cos 5x cos 2x.
Factor cos 7x − cos 3x.
Retain the leading minus sign.
−2sin 5x sin 2x.
Rewrite cos 4x cos x as a sum.
Use the sum and difference of 4x and x.
(cos 5x + cos 3x)/2.
Rewrite cos 4x sin x as a sum or difference.
Swap the factor order and apply the sine-cosine formula.
(sin 5x − sin 3x)/2, since sin(x − 4x) = −sin 3x.
Find sin 75° − sin 15° exactly.
Use average 45° and half-difference 30°.
2cos 45° sin 30° = √2/2.
Find cos 75° + cos 15° exactly.
Use the cosine-sum formula.
2cos 45° cos 30° = √6/2.
Solve sin 3x + sin x = 0 for 0° ≤ x ≤ 360°.
Factor as 2sin 2x cos x.
sin 2x = 0 gives x = 0°, 90°, 180°, 270°, 360°. The cos x = 0 roots are already included. These five distinct angles are the complete set.
Solve cos 4x − cos 2x = 0 on [0°, 360°].
Factor as −2sin 3x sin x.
sin 3x = 0 gives 0°, 60°, 120°, 180°, 240°, 300°, 360°. The sin x = 0 roots are already present.
Solve sin 4x + sin 2x = 0 for 0 ≤ x < 2π.
Use both families from 2sin 3x cos x = 0 and exclude 2π.
x = 0, π/3, π/2, 2π/3, π, 4π/3, 3π/2, 5π/3.
State the restriction when (sin 5x + sin 3x)/(cos 5x + cos 3x) simplifies to tan 4x.
Factor the original denominator first.
cos 4x cos x ≠ 0. Keeping only cos 4x ≠ 0 would incorrectly add inputs with cos x = 0.
Disprove cos A − cos B = 2sin((A + B)/2)sin((A − B)/2) using A = 60°, B = 0°.
Compare the two exact values.
The left side is 1/2 − 1 = −1/2; the proposed right side is 2 × 1/2 × 1/2 = 1/2. The correct formula has a leading minus.
11 / Recap
Section 1 of 11 · Use the average and half-difference of the angles