01 · Half-range
A periodic reading has minimum 8 and maximum 20. Find its midline and amplitude.
Hint
Use the midpoint and half the difference.
Worked solution
Midline 14; amplitude 6, in the reading’s units.
Understand · explore · practise
Build and interpret trigonometric models using amplitude, midline, period and phase. Explore circular motion manually, fit simple observations and check units, domains and model assumptions.
Before you startRadians, trig graph transformations and the R formula
01 / Connect a repeating situation to a graph
A trigonometric model approximates a repeating change: a height, displacement, reading or spatial profile. Begin by naming what the input and output measure, their units, and the part of the situation the model is intended to describe.
h(t) = H + A sin(ωt + φ)
Here H is the midline, |A| the amplitude, ω the angular frequency and φ the phase. The manual model connects the height of a point moving on a circle to a periodic graph.
h(t) = 6 − 2cos(2πt/8), with t in seconds and angles in radians.
t = 0/12 × T = 0.0000 s; h = 4.0000 m.
Range: 4 ≤ h ≤ 8 metres. One revolution takes 8 seconds.
Move time yourself. The circle and graph show the same height. This model assumes a fixed centre and constant angular speed; the notes remain readable independently.
02 / Read amplitude, midline and period separately
Midline H = (maximum + minimum)/2
Amplitude |A| = (maximum − minimum)/2
Period T = 2π/|ω| in radian form
H = (15 + 3)/2 = 9
The middle value is not the amplitude.
|A| = (15 − 3)/2 = 6
Amplitude is half the total vertical range.
ω = 2π/10 = π/5 radians per second
One full angular turn corresponds to one time period.
A phase or starting condition is still needed
The extrema and period alone do not locate the curve horizontally.
03 / Keep angle units and time units consistent
If the trig function is interpreted in radians, use ω = 2π/T. In a degree-based formula the angular coefficient is 360°/T. These are two representations of the same cycle, but their numerical coefficients must not be mixed.
One 12-second cycle:
sin(πt/6) in radians
sin(30°t) in degree notation, with t measured in seconds
The first coefficient has units radians per second; the second has degrees per second. If you change t from seconds to minutes, change the coefficient accordingly. Always state which convention you use.
04 / The initial value may not determine the direction
Starting at the lowest point: h(t) = 6 − 4cos(πt/6)
At t = 0 the cosine is 1, so the height is 2.
Starting at the highest point: h(t) = 6 + 4cos(πt/6)
The starting height is 10.
Starting at the midline and rising: h(t) = 6 + 4sin(πt/6)
A small positive input makes sine positive.
Starting at the midline and falling: h(t) = 6 − 4sin(πt/6)
The same initial height now has the opposite direction.
A single starting height can leave two possible phases. An observed direction, a peak time or another suitable observation can resolve that ambiguity.
05 / Model a point moving uniformly on a vertical circle
h(t) = 7 − 4cos(πt/10)
The minus cosine puts the start at the bottom.
h(0) = 3 m and h(10) = 11 m
These match the lowest and highest points.
h(5) = h(15) = 7 m
The point crosses the centre height twice per turn.
The range is [3, 11] m and the period is 20 s
These features match the geometry.
This idealisation assumes a rigid circle, a fixed centre and constant angular speed. Stops, acceleration or movement of a hanging seat would need additional modelling.
Pause, replay or seek freely. The notes explain the same idea and stay in view.
06 / Use the time of a known maximum or minimum
H = 8 and A = 6
Use the midpoint and half-range.
Choose cosine because its maximum occurs at input 0
Shift that maximum to t = 3.
h(t) = 8 + 6cos(π(t − 3)/9)
The radian coefficient is 2π/18.
Check h(3) = 14 and h(12) = 2
The minimum comes half a period later.
Writing cos(πt/9 − 3) would mean a phase of 3 radians, not a time shift of 3 seconds. Factor the input coefficient when translating between these descriptions.
07 / Fit a simple model to a stated repeating pattern
Suppose a smooth signal is specified to complete one cycle in 12 s. It starts at 6 and rises, reaches 10 at t = 3, returns to 6 at t = 6, reaches 2 at t = 9 and returns to 6 at t = 12.
h(t) = 6 + 4sin(πt/6)
This model matches all five stated observations. It predicts h(1.5) = 6 + 2√2. That prediction is a consequence of assuming a sinusoidal shape; the observations alone would not prove that the true signal has exactly this form.
Compare the prediction with an additional observation
Use an input that was not used to choose the parameters.
Look for systematic differences, not only rounding noise
A changing period or asymmetric rise/fall may make one sine wave unsuitable.
State the intended time interval
Repeated extrapolation assumes the same behaviour continues.
08 / Interpret a model written with both sine and cosine
Let α satisfy cos α = 3/5 and sin α = 4/5
Choose the acute phase α = arctan(4/3).
s(t) = 10 + 5sin(πt/6 + α)
The two components have the same input frequency.
Midline 10 cm; amplitude 5 cm; period 12 s
The amplitude is not 3 + 4.
The full-model range is [5, 15] cm
A shorter observation window may not attain both bounds.
s(0) = 14 cm
This checks the phase against the original expression.
09 / A repeating input can be distance rather than time
Midline 1.2 m and amplitude 0.3 m
These describe the vertical profile.
The pattern repeats every 5 m along x
This is a spatial wavelength, not a five-second period.
The range is [0.9, 1.5] m
This follows from the sine bounds.
A spatial profile by itself does not specify a travelling speed. A time-dependent model would need information linking position and time.
10 / Check that the model makes sense in its context
If a model describes a nonnegative depth, a negative predicted depth is a sign that the formula or its permitted interval needs reconsideration. Constant amplitude and period are assumptions; many real repeating quantities have noise, trends or changing cycles.
Its mathematical range is [−1, 5]
The formula is valid as a real-valued function.
A negative physical depth is not compatible with the stated meaning
It cannot describe a nonnegative depth over an entire cycle.
Revise the model or justify a restricted domain from the context
Do not silently discard negative predictions while claiming a full-cycle fit.
11 / Your turn
A periodic reading has minimum 8 and maximum 20. Find its midline and amplitude.
Use the midpoint and half the difference.
Midline 14; amplitude 6, in the reading’s units.
A cycle takes 15 s. Find the positive radian angular frequency.
Use 2π/T.
2π/15 radians per second.
Find the period of 4 + 2sin(πt/7), with t in minutes.
The radian coefficient is π/7 per minute.
T = 2π/(π/7) = 14 minutes.
A circle has radius 3 m, centre height 5 m and period 16 s. Give a height model starting at the bottom.
Use a negative cosine.
h(t) = 5 − 3cos(πt/8), in radians. Its range is [2, 8] m.
For the previous model, find h(4) and h(8).
The inputs are π/2 and π.
h(4) = 5 m and h(8) = 8 m.
Give two models with midline 7, amplitude 2, period 10 s and initial value 7, one rising and one falling.
Change the sign of a sine term.
7 + 2sin(πt/5) starts rising; 7 − 2sin(πt/5) starts falling. Values are in the stated output units.
A signal has midline 9, amplitude 4 and period 20 s, with a peak at t = 2 s. Give a model.
Shift a positive cosine maximum to t = 2.
9 + 4cos(π(t − 2)/10).
What is the time shift in cos(πt/4 − π/2), with t in seconds?
Factor π/4 from the bracket.
cos((π/4)(t − 2)), so the shift is 2 seconds to the right.
Find the amplitude and midline of 18 + 5sin t + 12cos t.
Combine the same-frequency terms.
Amplitude 13 and midline 18. The full-model range is [5, 31].
Interpret the horizontal repeat length of y = 2 + sin(πx/3), where x is in metres.
A full angular turn needs an increase 2π.
The profile repeats every 6 metres. This is not a time period.
Rewrite sin(πt/6), where t is in seconds, using τ measured in minutes.
Substitute t = 60τ.
sin(10πτ). Both describe a 12-second cycle, which is 0.2 minutes.
Why does matching five observations not prove that a real signal is exactly sinusoidal?
Many curves can pass through a finite set of points.
A sinusoid assumes a particular smooth repeating shape. Additional observations may reveal noise, changing amplitude, changing period or asymmetry. Matching points supports a model; it does not establish its universal accuracy.
Can 1 + 4sin t model a nonnegative water depth over a full cycle?
Check its entire range.
No: its range is [−3, 5]. The negative predictions conflict with nonnegative depth over a full cycle.
State two assumptions behind the simple circular height model.
Consider the circle and how the angle changes with time.
Examples: the centre remains fixed at a constant height; the radius is fixed; angular speed is constant; the point follows the circle without additional seat motion. Any two clearly stated assumptions are sufficient.
12 / Recap
Section 1 of 12 · Connect a repeating situation to a graph