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Recognising forces and drawing diagrams

Draw forces on one chosen body, distinguish contact forces from weight and avoid confusing motion arrows with force arrows.

Before you startParticles and modelling assumptions; SI units.

01 / Choose one body before drawing arrows

Each arrow is a force acting on that body.

Identify the interaction that causes each force.

A free-body diagram contains external forces on the selected body. Its motion or acceleration is not an extra force. The model diagrams here are schematic; unnumbered arrow lengths do not specify magnitudes.

Forces on the chosen bodyExplore

02 / Weight is the gravitational force

It acts towards the Earth in a local near-surface model.

01 · Interaction

What exerts the weight force on a book near the Earth?

Hint

Weight is not caused by the table.

Worked solution

The Earth exerts the gravitational force on the book. In the usual near-surface model it acts vertically downwards.

02 · Magnitude

A 2.5 kg body is modelled with g=9.8 m/s². Find its weight magnitude.

Hint

Use W=mg.

Worked solution

W=2.5×9.8=24.5 N.

03 · Falling

Does a freely falling object lose its weight merely because it has no supporting surface?

Hint

Separate gravity from support.

Worked solution

No. Gravity still acts. The supporting normal contact force can be absent while the weight remains.

03 / Normal means perpendicular to the surface

It need not be vertical or equal to weight.

Watch: the normal rotates with the surface

Pause, replay or seek freely. The notes explain the same idea and stay in view.

04 · Horizontal rest

A book rests on a horizontal table with only weight and normal reaction acting. Relate their magnitudes.

Hint

The book has no vertical acceleration.

Worked solution

N=W in this specified situation. The forces are opposite and their resultant is zero.

05 · Sloping surface

In which direction is the normal reaction on a body touching a smooth inclined plane?

Hint

Use the surface geometry.

Worked solution

Perpendicular to the plane, directed away from the surface. It is not generally vertical.

06 · Extra downward push

If a resting book also has a downward push P on a horizontal table, what is N?

Hint

Balance the vertical forces.

Worked solution

N=W+P, provided vertical acceleration is zero and these are the only vertical forces. Normal reaction is not automatically W.

04 / Friction opposes relative sliding or its tendency

A rough contact can have zero friction in a particular state.

07 · Sliding direction

A block slides right relative to a stationary rough floor. In which direction does kinetic friction on the block act?

Hint

Use relative sliding at the contact.

Worked solution

To the left along the floor.

08 · Static contact

Must a book resting on a rough horizontal table experience a nonzero friction force when no horizontal force acts?

Hint

Is there a tendency to slide?

Worked solution

No. With no horizontal sliding tendency in this simple situation, static friction can be zero. “Rough” means friction is available, not that it is always nonzero.

09 · Walking

Why is “friction always points opposite the object’s motion” an unreliable general rule?

Hint

The relevant motion is at the contact.

Worked solution

Friction opposes relative slipping or its tendency between surfaces. For a foot pushing backwards on the ground, static friction from the ground can act forwards on the person.

05 / Tension and thrust describe different interactions

A flexible string pulls along its length.

10 · Hanging lamp

Draw or describe the two forces on a lamp at rest on a light vertical string, ignoring air effects.

Hint

Choose the lamp as the body.

Worked solution

Weight downward and tension upward. In this two-force stationary model their magnitudes are equal.

11 · Rod push

What can a rigid connecting rod transmit that an ideal flexible string cannot?

Hint

Consider compression.

Worked solution

A rod can transmit a pushing compressive force, often called thrust in this setting, as well as tension if the model permits. An ideal flexible string cannot push.

06 / Name fluid forces by their physical role

Drag, buoyancy, lift and thrust are not interchangeable.

12 · Drag

In what direction does drag act relative to an object’s motion through the surrounding fluid?

Hint

Use motion relative to the fluid.

Worked solution

Opposite the relative motion through the fluid. The relevant velocity is not always velocity relative to the ground.

13 · Floating rest

A body floats at rest with only vertical weight and buoyancy. Compare their magnitudes.

Hint

Use the stationary two-force model.

Worked solution

The upward buoyant force equals the downward weight. This equality depends on the stated equilibrium conditions.

14 · Aircraft

Name the four main forces in a simplified steady, level flight model.

Hint

Separate propulsion from aerodynamic support.

Worked solution

Weight downward, lift upward, thrust forward and drag backward. With constant velocity in this idealised arrangement, opposite totals balance; lift and thrust are distinct.

07 / Do not mix forces on different bodies

An interaction pair belongs on two different diagrams.

15 · Book and table

Should “book pushes down on table” appear on a diagram of forces acting on the book?

Hint

Identify the receiver of that force.

Worked solution

No. It acts on the table. The corresponding contact force from the table on the book belongs on the book’s diagram.

16 · Motion arrow

A block moves right. Should you automatically add a rightward force labelled “motion”?

Hint

Motion need not require a resultant in its direction.

Worked solution

No. Draw only identified interactions. A body can move at constant velocity with zero resultant force, or move right while a leftward resultant slows it.

08 / Audit every arrow

State the body, interaction and direction.

Draw weight separately from contact support. Normal is perpendicular; friction concerns relative slipping. Tension pulls along a string. Fluid forces depend on the interaction. Balance forces only when the model’s acceleration conditions justify it, and never mix forces on different bodies.

Section 1 of 8 · Choose one body before drawing arrows